Question: HELP! My java code won't fully run? It gets stuck, and I don't get it. Help me please! import java.util.Scanner; public class Course { public
HELP! My java code won't fully run? It gets stuck, and I don't get it. Help me please!

import java.util.Scanner;
public class Course {
public double finalGrade;
public void calculateFinalGrade() {
Scanner in = new Scanner(System.in);
System.out.println("What is the average grade for exams? ");
double examAverage = in.nextDouble();
System.out.println("What is the average grade for quizzes? ");
double quizzesAverage = in.nextDouble();
System.out.println("What is the average grade for homework? ");
double homework = in.nextDouble();
finalGrade = Math.round((examAverage * 0.5) + (quizzesAverage * 0.3) + (homework * 0.2));
}
public static void main(String[] args) {
System.out.println("**** Course 1 ****");
Course myCourse1 = new Course();
myCourse1.calculateFinalGrade();
System.out.println("**** Course 2 ****");
Course myCourse2 = new Course();
myCourse2.calculateFinalGrade();
double totalAverage = (myCourse1.finalGrade + myCourse2.finalGrade) / 2;
System.out.printf("The average grade of the two courses is: %.2f", totalAverage);
//Using conditionals check if the average grade is either an A, B, C, D, or F and display it on the screen.
//This is the criteria you need to use and check:
//A: totalAverage >= 90.
//B: totalAverage >= 80 but
//C: totalAverage >= 70 but
//D: totalAverage >= 60 but
//F: totalAverage
//***ENTER YOUR CODE HERE***
//displaying the letter grade according to the total average
if(totalAverage >= 90){
System.out.println("Your grade is A");
}else if(totalAverage >= 80 && totalAverage
System.out.println("Your grade is B");
}else if(totalAverage >= 70 && totalAverage
System.out.println("Your grade is C");
}else if(totalAverage >= 60 && totalAverage
System.out.println("Your grade is D");
}else if(totalAverage
System.out.println("Your grade is F");
}
}
}
Course.java Problems Javadoc Declaration Console Coverage Properties
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