Question 6 Not yet answered Marked out of 1.00 P Flag question Suppose that a mass...

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Question 6 Not yet answered Marked out of 1.00 P Flag question Suppose that a mass of 100 g stretches a spring 5 cm. If the mass is set in motion from its equilibrium position with a downward velocity of 24.40 cm/sec, and if there is no damping then we can obtain the equation modelling this system as follows: The spring constant is k= (100g) (980cm/sec²) 5cm 19600. Hence 100u" +19600u = 0 can be simplified to u" +196u = 0. In this case the initial values are u(0)=0 and u'(0)=24.40. By using the information given above, determine the value of u(3.2), the position of the mass at 3.2 seconds. (Write the numerical value of the answer into the box) Answer: Question 6 Not yet answered Marked out of 1.00 P Flag question Suppose that a mass of 100 g stretches a spring 5 cm. If the mass is set in motion from its equilibrium position with a downward velocity of 24.40 cm/sec, and if there is no damping then we can obtain the equation modelling this system as follows: The spring constant is k= (100g) (980cm/sec²) 5cm 19600. Hence 100u" +19600u = 0 can be simplified to u" +196u = 0. In this case the initial values are u(0)=0 and u'(0)=24.40. By using the information given above, determine the value of u(3.2), the position of the mass at 3.2 seconds. (Write the numerical value of the answer into the box) Answer:

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