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2. Let A be as in the problem 1. We saw that A is not diagonalizable, but all hope is not lost! We can still manipulate A so as to gain a computational advantage. A generalized eigenvector of rank m corresponding to the eigenvalue A is a vector 17 for which (A AI)m1i = 0. (a) Find an eigenvector for A = 1, call it 171. (b) Find an eigenvector for A = 2, call it 172. (c) Find a generalized eigenvector of rank 2 for A = 2, i.e., nd a vector '03 satisfying (A2I )2173 = 6 (d) Let P = vi 173'; '03 and compute P'lAP. What do you notice about this product