Help with last part because the confidence interval

A poll asked college students in 2016 and again in 2017 whether they believed the First Amendment guarantee of freedom of the press was secure or threatened in the country today. In 2016, 2483 of 3094 students surveyed said that freedom of the press was secure or very secure. In 2017, 1800 of 2015 students surveyed felt this way. Complete parts (a) and (b). OD. HO: P1 # P2 OE. Ho: P1 P2 Identify the test statistic. Z= -8.61 (Round to two decimal places as needed.) Identify the p-value. p-value = 0.000 (Round to three decimal places as needed.) Since the p-value is less than the significance level of a = 0.05, reject the null hypothesis. There is sufficient evidence to support the claim that the 2016 proportion is different from the 2017 proportion. b. Use the sample data to construct a 90% confidence interval for the difference in the proportions of college students in 2016 and 2017 who felt freedom of the press was secure or very secure. How does your confidence interval support your hypothesis test conclusion? The 90% confidence interval is ( - 0.107 , - 0.075 ). (Round to three decimal places as needed.) Because the confidence interval it appears that the two proportions are equal. This conclusion supports the hypothesis test conclusion