Help with response : Do you agree with how the peer used the vocabulary? Did the peer handle the negatives in the formulas accurately?

Week 1 Discussion 1

Evaluating Algebraic Expressions

My birthday is January 23, 1985 or1/23/85

So,a=1

b= -23

andc= 85

1. becomes

For this equationvariablea will become a 1 andvariableb will be negative 23 with theexponentof 3 for both.Fist I will multiply theintegerswith theirexponentsbeingandbeing In the last set subtracting from a negative makes it a positive so it's more like adding giving me 12,168 for the answer.

2.becomes

Again, using myintegers1 forvariablea and -23 forvariableb I will first do the parentheses.thenbecomes.In the first parenthesis subtracting a negative changes to adding a positive making the answer 24. In the next parentheses I first solve for the exponents with the first becoming 1 and the second being -529.Then I will multiple the middle equation of 1 times -23 giving me a negative 23.Now to add inside the brackets.1 plus -23 is subtracting making it 22, then adding that to -529 which again is subtracting making the negative into a positive giving me 507.For the last step I will multiply the 507 from inside the bracket to the 24 on the outside to get 12,168.

1. (for this problem I'm going to show the equation then explain it.)

This time using all threevariablesand adding in myintegersI'll first solve for the numerator.With a negative number first ill just subtract and keep the number negative giving me -62.For the denominator first, I'll multiply -23 by 2 giving me -46 and then subtract leaving the denominator -45.Since there is no commondivisorfor 62 and 45is thelowest term.