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Let f(x) = x2 -3X on [4, 7]. Use the NT to determine if there is a solution to f(x) = 10 in the interval between 4 and 7. If so, nd the value of c in the interval such that 1'03) = 10. a.) 0 x) is continuous on [4, 7] . 10 is between f(4) =4 and ?) = 28 - c = "ID - f(x) is continuous on [4, 7] . 10 is between f(4) =4 and ?) = 28 o c= -2,C=5 d.) . x) is continuous on [4, 7] . 10 is between f(4) =4 and f(7) = 28