Question: Help with this test please I am a little confused Algebra 1 tutor needed Select the equation in which the graph oF the line has

Help with this test please I am a little confused Algebra 1 tutor needed

Help with this test please I am a little confused Algebra 1tutor needed Select the equation in which the graph oF the linehas a negative slope, and the uniintercept equals 4. 05x+w=4 DEXEv=-4 04x+16ir=ZL'.| D&+@=E QU EST | O N 2 Select the equation thatcontains the point [3. E], and In which the slope equals 1.

Select the equation in which the graph oF the line has a negative slope, and the uniintercept equals 4. 05x+w=4 DEXEv=-4 04x+16ir= ZL'.| D&+@=E QU EST | O N 2 Select the equation that contains the point [3. E], and In which the slope equals 1. Qv+=x+ Qv6=x3 v+=31 Dv =3x QUESTION 3 Given a positive slope of 3 and a uniintercept of 3. identify the corresponding equation. Dv= sx+3 oy=3xe Dv3=8x or=mxm a: Question Coinpietton Status: I Select the equations that are equivalent to the equation y + 5 - _ 30 1) . Select all that apply. m= 3x2 ay= 4x5 m3x+y=2 a ~4x+v= 5 Q U EST | O N 5 which of the following represents the equation of a line with a slope of 2 and a \ Intercept of [0. 4]? @Zx+r=4 @y=2x& av-O-Kxll} 9y=2x+4 3 \"Ellis .Sau Answer QUESTION 6 Select the equation ofthe line In which the xinbercept Is 2, and the ylntemept is 8. @y8=XO @yE- 2(x4} @y=[x4J elf3- 4[x0} which of the following represents an equation of a line with a slope of 3 and that passes through the point (2. 8]? 0 3X + y = 2 3 3X + y = 2 0 3X + V = 2 2 0 2x If = 12 QUESTION 3 | 4mm: SIUIAI'ISWIr Select the descriptions that are true of the equation &x + y = E . Select all that apply. D The slope = 4 D The ylntercept equals 8 D The line moves up from left no right [1 The xlnteroept is positive QUESTION 9 39F\" ! Select the equation that Is represented by the Following graph: QUESTION 10 Select the at: nation of the line graphed below: I- III-- I\" III-Id .- II-VAI I- II'IIII I- In.\" 'Allll Er'i IIIIIIII IIIIIIIE Ill-IIIII = Iii: HERE v+7=1(x+6] BV-?=1[X-l av+6=10+71 BV-5=1[X-7J

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