Question: HELP!!!! Written in C 1 #include 2 #include 3 4 extern char **environ; 5 void output(char *a[], char *b[]) { 6 int c = atoi(a[0]);

HELP!!!!

Written in C

1 #include

2 #include

3

4 extern char **environ;

5 void output(char *a[], char *b[]) {

6 int c = atoi(a[0]);

7 for (int i = 0; i < c && b[i]; ++i) {

8 printf("%s", b[i]+2);

9 }

10 }

11

12 void main(int argc, char *argv[]) {

13

14 switch (argc) {

15 case 1:

16 for (int i = 0; environ[i]; ++i) {

17 printf("%s", environ[i]);

18 }

19 break;

20 default:

21 output(argv + 1, environ + 1);

22 exit(argc);

23 }

24 }

After executing the command $ ./m0 (assuming that the code above was compiled with $ gcc m0.c -o m0), suppose that the output is

A=5

B=4

C=8

D=0

E=1

What is the output of executing this command $ ./m0 2 3 4 5?

(atoi(str) converts the string argument str to an integer)

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