Question: Here are the formulae by which 7 and 0 are changing: r(t) = 57:2 + 2, 6(t) = g Er Recall that the area of

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Here are the formulae by which 7\" and 0 are changing: r(t) = 57:2 + 2, 6(t) = g Er Recall that the area of a sector in a circle is given by the formula %7'29 Where the central angle 6 is measured in radians. (a) (2 marks) What is the initial area of this sector? That is, what is A when t = 0? (b) (3 marks) How fast is the area A changing at t = 1

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