Question: Here is the code for LU factorization: function A=LU_decomposition (A) [ rows_A , cols_A ] = s i z e (A) i f rows_A =

![rows_A , cols_A ] = s i z e (A) i f](https://dsd5zvtm8ll6.cloudfront.net/si.experts.images/questions/2024/09/66f39bcfb983f_16766f39bcf6997c.jpg)
Here is the code for LU factorization:
function A=LU_decomposition (A)
[ rows_A , cols_A ] = s i z e (A)
i f rows_A = cols_A
error ( A matrix must be square . )
end
n = rows_A ;
f o r col = 1: n1
f o r row = col +1:n
f a c t o r = A(row , col ) / A( col , col ) ;
A(row , col ) = f a c t o r;
f o r k = col +1: cols_A
A(row , k) = A(row , k)f a c t o rA( col , k) ;
end
end
end
end
a. Write a function that finds the inverse of a square matrix column-by-column using LU factorization code that you developed in problem 3. The input is a square matrix. b. Use the code you developed in part a to compute the inverse of the following matrix Print the result 3 0 -1 10 -7 0 6 4 0 3 2 1 A=
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