Question: Here is what we got from running the equation: Call: lm(formula = lifeExpectancyRating ~ happinessRating, data = WHR2024) Residuals: Min 1Q Median 3Q Max -0.33149

Here is what we got from running the equation: Call: lm(formula = lifeExpectancyRating ~ happinessRating, data = WHR2024) Residuals: Min 1Q Median 3Q Max -0.33149 -0.05716 -0.00660 0.05376 0.35891 Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) -0.065730 0.043706 -1.504 0.135 happinessRating 0.106062 0.007729 13.722 <2e-16 *** --- Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1 Residual standard error: 0.1076 on 138 degrees of freedom Multiple R-squared: 0.5771, Adjusted R-squared: 0.574 F-statistic: 188.3 on 1 and 138 DF, p-value: < 2.2e-16 1 0.6660954

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