Question: HERE TBM1=FA.CBE m so FA.CBE is =11.221 m usethis value. same for TBM2 ** ABCDEF provided in Questions 1 and 2 represents your 6-digit student

** ABCDEF provided in Questions 1 and 2 represents your 6-digit studentnumber. Please consider accordingly. Q1. Table 1 overleaf (Q1) indicates a levellingHERE TBM1=FA.CBE m so FA.CBE is =11.221 m usethis value. same for TBM2survey carried out to establish existing ground levels along the centre line

** ABCDEF provided in Questions 1 and 2 represents your 6-digit student number. Please consider accordingly. Q1. Table 1 overleaf (Q1) indicates a levelling survey carried out to establish existing ground levels along the centre line of a proposed road. (0) (iv) (v) Determine the reduced levels using the height of plane of collimation (HPC) method. (10 pts) Find misclosure (if any) and carry out the usual mathematical checks to determine if this misclosure is due to errors in computation. (20 pts) Distribute the actual misclosure and obtain the corrected reduced levels. (15 pts) Using paper provided to you, sketch the longitudinal section of corrected reduced levels along the existing ground profile from chainage 0-80 m. (20 pts) What is the slope between Chainage point 20 m and Chainge point 70 m? (15 pts) Back sight (m) 3.241 0.281 3.125 4.000 0.511 1.768 1.453 3.058 2.587 Intermediate sight (m) 1.991 2.068 2.426 0.228 2.244 4.081 1.268 0.866 TBM, FA.CBE m, TBM, FA.CBE m Foresight (m) 3.296 0.405 3.274 1.927 1.949 3.056 2.777 1111 2.253 Table 1. Question I HPC (m) Reducel Level Correction (m) Corrected RL (m) Remarks TBM Chainage point 10m Chainage point 20m Change Point 1 Change Point 2 Chainage point 30m Chainage point 40m Change Point 3 Change Point 4 Change Point 5 Chainage point 50m Chainage point 60m Change Point 6 Chainage point 70m Change Point 7 Chainage point 80m Change Point 8 TBM

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