Hexane has overflowed from a storage tank into secondary containment. The pit is square with a length of 4 m on each side. The hexane layer is 10 cm thick at the bottom of the pit. We can assume that there is a 30 cm thick layer of stagnant air over the hexane due to the pit walls. The temperature on this particular day is 25°C and the atmospheric pressure is 1 atm. Identify which limiting case for the general diffusion equation this situation represents and explain your reasoning for choosing that case. Based on the information above and the limiting case you identified, find the flux of hexane from the pit and, based on this flux, estimate how long it will take for the hexane to fully evaporate. How do you think the real time for evaporation will compare to your estimate and why do you think that will be the case?

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This situation represents the limiting case of steadystate diffusion because the hexane has been overflowing from the storage tank for some time and h... View the full answer