Hi, can someone verify this solution? and if it is correct can you explain how S2 is found? I cant seem to get any value close to 2.

Determine the volumetric cell productivity for the fermenter configuration identified in Figure Q3 below. The system is operated at a feed rate of 15103m3h1 with initial glucose concentration S0=10kgm3. Total bioreactor volume (V1+V2) is 0.10m3 and V1=V2. The microorganism grown is Examococcus kaicheerios. E. kaicheerios obeys Monod kinetics with m=0.4h1 and KS=2kgm3. The cell yield coefficient on glucose is YX/S=0.5gg1. As usual, state all assumptions. Figure Q3. Find volumetric cell productivity, F=15103m3/h,S0=10kg/m3,V1=V2=0.05m3 =D=Ks+SmKs=VF For the first tank, D=0.3,S1=6kg/m3x1=Ysx(S0S1)=2kg/m3 For the second tank, D=, Mass balance of cell in tank 2 , At ss, 0=F(x1)F(x2)+x2Vx2=DDx1=0.30.3(2) mass balance of substrate in tank 2 , At ss, 0=D(S1)D(S2)Yx/sx2S2=2kg/m3 After substituting the equations and solve simultaneously, x2=0.5(52)+2=4kg/m3Productivity,P=Dx=0.3(4)=1.2m3hkg