Question: hi, first pages are the completed first part, accordingly answer part 2 and 3. please answer each i posted two questions on this and got

hi, first pages are the completed first part, accordingly answer part 2 and 3. please answer each i posted two questions on this and got an empty answer. i dont have many questions left. thank you i will thumbs up!  hi, first pages are the completed first part, accordingly answer part
2 and 3. please answer each i posted two questions on this
and got an empty answer. i dont have many questions left. thank
you i will thumbs up! up to here are answers to useup to here are answers to use
here starts what needs to be answered. Part 1: Cltric Acid +here starts what needs to be answered.
Sodium Hydrogen Carbonate Part 2: Hydrochloric Acid + Magnesium Part 3: Hydrochloric

Part 1: Cltric Acid + Sodium Hydrogen Carbonate Part 2: Hydrochloric Acid + Magnesium Part 3: Hydrochloric Acid + Magnesium Oxide Part 1: Citric Acid + Sodium Hydrogen Carbonate Part 1: Citric Acid + Sodium Hydrogen Carbonate The strategy with this set of calculations is to determine the amount of heat transferred per one mole of the limiting reagent in the experiment. The limiting reagent in Part 1 is sodium hydrogen carbonate. To determine the amount of heat transferred in the reaction we use H=msT. Once this value has been calculated then the units are converted from Joules to kilojoules. Density of citric acid solution 1.02gmL1 Mass of citric acid (d=m/V) Specific heat capacity of citric acid solution 4.68Jg10C1 Change in temperature for reaction H(msT) Mass NaHCO3(g) Moles NaHCO3(mol) mol H per mole of NaHCO3[H=molesNaHCO3H]Jmol1 H per 3 moles of NaniCO3Jmol1 H per 3 moles of NaHCO3 in kJ/mol(1kJ=1000J) kJJolm1 Density of cithic Acid Solution =1.02gmL Mass of citic Acid (d=m/v)=40ggm.40.8gm. m=dv.=1.020ml=0.0408tg40.8gn 4 Specific Heat copauily of citric =4.68JJ1C1 Acid solution 5 Change in temperature =(4=0.8m11.02g/m))4.68J/gC15.4. =2940.5J2946.5J 6 moles of NaHlO3 reacted =30.0408g/192.124gd - 6.00064mol. =0.00064 mole. 7 Mass or NaHCCO3=0.00064mol84g/mol =0.054g. 9H per 3 moles of NaH3=459.463=1378.38kJ/mat. 10. H per 3 mokes of NaHllg in kJ/mos=1.378kJ/mole. Part 2: Hydrochloric Acid + Magnesium The strategy for these calculations are similar to those in Part 1. In Part 2, magnesium reagent. Volume of hydrochloric acid solution Density of hydrochloric acid solution Mass of hydrochloric acid solution (d=m/V) Specific heat capacity of hydrochloric acid solution mL1.02gmL1 Change in temperature for reaction H(msT) Mass of magnesium Moles of magnesium* mol H per mole of MgO=(molesMgH) 4.68J10g1C1 C H per 1 mole Mg(1kJ=1000J) kJkolmol1 * Use the mass and atomic mass of Mg **The amount of heat we measured is, according to the equation below, per 1mol of Mg. Mg(s)+2HCl(aq)MgCl2(aq)+H2(g) Part 3: Hydrochloric Acid + Magnesium Oxide In Part 3 magnesium oxide is the limiting reagent. Volume of hydrochloric acid solution mL Density of hydrochloric acid solution 1.02gmLL1 Mass of hydrochloric acid solution (d=m/V) Specific heat capacity of hydrochloric acid solution 4.68Jg10C1 Change in temperature for reaction C H(msT) Mass of magnesium oxide Moles of magnesium oxide* mol H per mole of MgO=(molesMgOH)Jmol1 H per 1 mole MgO(1kJ=1000J) kJmol1 * Use the mass and molar mass of MgO **The amount of heat we measured is, according to the equation below, per 1 mole of N MgO(s)+2HCl(aq)MgCl2 (aq) +H2O(l)

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