Hi! I don't understand question #2. Could you please explain to me?

HW 6 Text book: Page 466 - 467, Question #s : 9.8 Page 476 -479, Question #s : 9.22, 9.26 Page 489 - 492, Question #s : 9.40, 9.50 The approximate costs for a 30-second spot for various cable networks in a random selection of cities are shown below. 61 12 6 40 38 27 93 15 13 10 23 40 a. What is a point estimate for the population mean / ? b. Find 99% confidence interval for / . 2. Nielson Media Research wants to estimate the mean amount of time (in minutes) that full-time college students spend watching television each weekday. Find the sample size necessary to estimate that mean with a 15-minute sampling error. Assume 96% confidence level is desired. Also assume that a pilot study showed that the standard deviation is estimated to be 112.2 minutes. 3. A random sample of the number of farms (in thousands) in various states follows. Estimate the mean number of farms per state with 97% confidence. Assumeo = 30. 47 95 54 33 64 4 8 57 8 90 3 49 4 44 79 80 68 7 15 21 52 6 78 90. 4. In a poll of 2000 likely voters, 960 say that the US spends too little on fighting hunger at home. Find a 96% confidence interval for the true proportion of voters who feel this way. a. Find a point estimate for p, the population proportion who thought US spends too little on fighting hunger at home. b. Find a 96% confidence interval for p. . A recent study indicated that 29% of the 100 women over age 55 in the study were widows. (a) How large a sample must you take to be 90% confident that the estimate is within 0.05 of the true proportion of women over age 55 who are widows? (b) If no estimate of the sample proportion is available, how large should the sample be? 29