Hi. I have been having some difficulties with the following assignment. Everything I try outputs an error
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Hi. I have been having some difficulties with the following assignment. Everything I try outputs an error message and no amount of research is helping in any way.
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!!! 5 Assignments: 202209- Intro to P X File Edit View Run Kernel Tabs Settings Help + Filter files by name Name Simple + Andruskie... BasicExa... Challenge... Challenge... Condition... core.141 core.83 CSCI 1040... CSCI1040... F22-lab00... hist.jpg INTRO.ipy... Lab#1.ipy... Lab#2.ipy... Lab#3.ipy... Lab#4.ipy... Lab#5.ipy... Lab#6.ipy... Loops.ipy... Loops&Li... 1C Mostly sunny 0 https://hub.science.ontariotechu.ca/user/100860820/lab/workspaces/auto-A?redirects=1 3 Q F22-lab007_assi (auto-A: 3) - Jup X Last Modified a month ago 2 months ago 2 months ago 2 months ago 2 months ago 15 hours ago 15 hours ago 10 days ago 3 days ago seconds ago 4 days ago 2 months ago 2 months ago 2 months ago a month ago a month ago 21 days ago 11 days ago 2 months ago a month ago Module 6 - Part 2 - Plots F22 X 8 + X 17 Your Name Python 3 (ipykernel) | Idle Homework Help - Q&A from On X + [ ]: # test cases F22-lab007_assignment.ipynlX Code import datetime datetime.datetime (2020, 1, 1).weekday() #returns 2 [5]: # your code here import datetime datetime.datetime (2020, 1, 1). weekday() def getDay (date): O Search Task 1 Write a function getDay (date) that takes a space separated string as a date (MM DD YYYY) and it returns the week day that date was on (e.g. Monday, Tuesday,...). Obs. do not use Python string built-in functions like .split(). Hint: First of January was on Wednesday. The datetime library can assist you with consulting the day of the week. .weekday() - Returns the day of the week as an integer, where Monday is 0 and Sunday is 6. For example, date (2002, 12, 4).weekday() == 2, a Wednesday getDay (01 01 2020') #returns "Wednesday" H Mode: Edit Davey't 5} X MX Python 3 (ipykernel) T ENG US O1 * B Ln 5, Col 18 F22-lab007_assignment.ipynb x O + 10:17 AM 2022-11-08 !!! 5 Assignments: 202209- Intro to P X File Edit View Run Kernel Tabs Settings Help + Filter files by name Name Simple + Andruskie... BasicExa... Challenge... Challenge... Condition... core.141 core.83 CSCI 1040... CSCI1040... F22-lab00... hist.jpg INTRO.ipy... Lab#1.ipy... Lab#2.ipy... Lab#3.ipy... Lab#4.ipy... Lab#5.ipy... Lab#6.ipy... Loops.ipy... Loops&Li... 1C Mostly sunny 0 https://hub.science.ontariotechu.ca/user/100860820/lab/workspaces/auto-A?redirects=1 3 Q F22-lab007_assi (auto-A: 3) - Jup X Last Modified a month ago 2 months ago 2 months ago 2 months ago 2 months ago 15 hours ago 15 hours ago 10 days ago 3 days ago seconds ago 4 days ago 2 months ago 2 months ago 2 months ago a month ago a month ago 21 days ago 11 days ago 2 months ago a month ago Module 6 - Part 2 - Plots F22 X 8 + X 17 Your Name Python 3 (ipykernel) | Idle Homework Help - Q&A from On X + [ ]: # test cases F22-lab007_assignment.ipynlX Code import datetime datetime.datetime (2020, 1, 1).weekday() #returns 2 [5]: # your code here import datetime datetime.datetime (2020, 1, 1). weekday() def getDay (date): O Search Task 1 Write a function getDay (date) that takes a space separated string as a date (MM DD YYYY) and it returns the week day that date was on (e.g. Monday, Tuesday,...). Obs. do not use Python string built-in functions like .split(). Hint: First of January was on Wednesday. The datetime library can assist you with consulting the day of the week. .weekday() - Returns the day of the week as an integer, where Monday is 0 and Sunday is 6. For example, date (2002, 12, 4).weekday() == 2, a Wednesday getDay (01 01 2020') #returns "Wednesday" H Mode: Edit Davey't 5} X MX Python 3 (ipykernel) T ENG US O1 * B Ln 5, Col 18 F22-lab007_assignment.ipynb x O + 10:17 AM 2022-11-08
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