Hi, I need help solving 12, 14, and 15.

78 Chapter 1 / Limits and Continuity x- 1 13. (a) lim - x = 2, 1.5, 1.1, 1.01, 1.001, 0, 0.5, 0.9. *-1x3 - 1 0.99, 0.999 y = f(x) * +1. t = 2, 1.5, 1.1, 1.01, 1.001, 1.0001 (b) lim x - 1+ x3 - 1 *+1 (c) lim - x3 - 1' x = 0, 0.5, 0.9, 0.99, 0.999, 0.9999 Vx +1-1 x = 40.25, 40.1, +0.001, 14. (a) lim x -+ 0 +0.0001 Figure Ex-9 Vx +1+1. x = 0.25, 0.1, 0.001, 0.0001 10. For the function g graphed in the accompanying figure, find b) lim x - 0+ (a) lim g(x) (b) lim g(x) x+ 1+1. (c) lim x = -0.25, -0.1, -0.001, (c) lim g (a) (d) 8(1). x - 0 X -0.0001 sin 3x x = 10.25, 40.1, 40.001, +0.0001 y = 8(x) 15. (a) lim x - 0 (b) lim cos x x - -1x+1 x = 0, -0.5, -0.9, -0.99, -0.999, -1.5, -1.1, -1.01, -1.001 16. (a) lim tan (x + 1) x - - 1 x +1 -; x =0, -0.5, -0.9, -0.99, -0.999. -1.5, -1.1, -1.01, -1.001 (b) lim sin (5x) x - 0 sin (2x)' x = 10.25, +0.1, +0.001, +0.0001 Figure Ex-10 17-20 True-False Determine whether the statement is true or false. Explain your answer. 11-12 (i) Complete the table and make a guess about the limit indicated. (ii) Confirm your conclusions about the limit by 17. If f(a) = L, then limx -> a f(x) = L. graphing a function over an appropriate interval. [Note: For 18. If limx->a f(x) exists, then so do limx -> a- f(x) and the inverse trigonometric function, be sure to put your calculat- limx -> at f(x). ing and graphing utilities in radian mode.] 11. f(x) = ex - 1 19. If limx -> a- f(x) and limx -> at f(x) exist, then so does ; lim f(x) limx -> a f(x). x-0 X -0.01 -0.001 20. If limx - at f(x) = too, then f(a) is undefined. -0.0001 0.0001 0.001 0.01 f(x 21-26 Sketch a possible graph for a function f with the speci- A Table Ex-11 fied properties. (Many different solutions are possible.) 21. (i) the domain of f is [-1, 1] 12. f(x ) = sin 2x lim f(x) (ii) f (-1) = f(0) = f(1) =0 X x -+ 0 (iii) lim f(x) = lim f(x) = lim f(x) =1 x - - 1+ X - 0 ' -0.1 -0.01 -0.001 x - 1 - 0.001 0.01 22. (i) the domain of f is [-2, 1] f(x 0.1 (ii) f ( -2) = f (0) = f(1) =0 Table Ex-12 (iii) lim f(x) = 2, lim f(x) =0, and * - 2+ limx -1- f(x) =1 13-16 (i) Make (i) the domain of f is (-0