Hi I need help with attached problem. I have also attached an example that I am hoping will help make sense of what I need help with. Please let me know what goes in the chart empty boxes as seen in the example.

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Fill in the P (X= x) values to give a legitimate probability distribution for the discrete random variable X, whose possible values are 1, 3, 4, 5, and 6. Value x of X P( X = x) 3 0.17 4 0.27 5 0.10 6 X 5 ?? QUESTION Fill in the P (X=x) values to give a legitimate probability distribution for the discrete random variable X, whose possible values are - 2, 2, 4, 5, and 6. Value x of X P(X = x) - 2 0.27 2 0.10 4 0.29 EXPLANATION The values that the discrete random variable X may take are -2, 2, 4, 5, and 6. Thus, it must be that we have the following. P(X= -2) +P(X=2) +P(X=4) +P(X=5) +P(X=6)=1 In the above, OSP(X=x) $1 for x= -2, 2, 4, 5, 6. From the information given, we have this. 0.27 + 0.10 + P(X=4) + P(X=5) +0.29 =1 That gives us the following. P (X=4) + P(X=5)=1- (0.27 + 0.10 + 0.29)=0.34 To complete the probability distribution, then, we must choose P (X"=4) and P (X"= 5) to be any numbers from 0 to 1 such that this holds. P(X=4) + P(X=5)=0.34 For example, we could choose P (X= 4) = 0.12 and P (X=5)=0.22. ANSWER Here is one possible answer. Value x of X P(X = x) -2 0.27 2 0.10 4 0.12 5 0.22 6 0.29