Question: Hi I'm taking a numerical analysis course and we are using C/ C++ syntax program in the course. I'm a little confused on how to

Hi I'm taking a numerical analysis course and we are using C/ C++ syntax program in the course. I'm a little confused on how to fill in this code for interval bisection to get it to work. Can someone help me out?  Hi I'm taking a numerical analysis course and we are using
C/ C++ syntax program in the course. I'm a little confused on

The interval bisection method works iff the function is continuous and you can establish an initial left & right guess, such that: f(left) and f(right) have different signs (i.e.: one is positive and the other negative) COMPILE THIS CODE BY RUNNING: gcc interval_bisection04_lab.c-Im The -Im links with the math library #include #include #include double f1 (double x) { double yi y = x*x-2; return y; double f2 (double x) // three roots, Il -3 - sqrt(3) = -4.732050, 11 -3 + sqrt(3) = -1.267949, { double y; y = x*x*x - 30*x - 36; return y; } // f points at a function with one double input and a double output int interval_bisection(double (*f)(double x), double left, double right, double epsilon, int maxreps, double results[2]) // return 0 failure, else 'numreps' (>= 1) // 'maxreps' is the maximum iterations through the loop { // example of a valid function call to f: || double fl; // fl = f(left) ; // The algorithm should continue until 'maxreps' iterations have been // performed or the width of the interval is within 'epsilon' Il your code goes here! }

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