Considering that Rxn 2 is taking place in the cathode while Rxn 1 is at the anode,

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Considering that Rxn 2 is taking place in the cathode while Rxn 1 is at the anode, determine the free energy change in kJ given the following. Please show a complete solution. Note that this happens at a room temp.

PI A2+ (0.59 M) + 2e -> A E cell = 1.70 V R2 2 B3+ (0.41 M) + 3e -> EO cell = 1.49 v

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Finance Applications and Theory

ISBN: 978-0077861681

3rd edition

Authors: Marcia Cornett, Troy Adair

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Posted Date: Jul 27, 2021 01:16 AM

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Considering that Rxn 2 is taking place in the cathode while Rxn 1 is at the anode,

Question:

A2+ (0.59 M) + 2e¯ -> A Ecell = 1.70 V в3+ (0.41 м) + 3е -> В cell = 1.49 v %3D A2+ (0.59 M) + 2e¯ -> A Ecell = 1.70 V в3+ (0.41 м) + 3е -> В cell = 1.49 v %3D

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Finance Applications and Theory

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