Question: Hi so I have done this problem multiple time now and I do not know if I am correct. I would like an explanation on
Hi so I have done this problem multiple time now and I do not know if I am correct. I would like an explanation on where I am going wrong. Thank you I just need it to be checked


Consider the game of rock-paper-scissors to be an experiment. In the long run, roommate A chooses rock 62% of the time, and roommate B chooses rock 62% of the time; roommate A selects paper 16% of the time, and roommate B selects paper 23% of the time; roommate A chooses scissors 22% of the time, and roommate B chooses scissors 15% of the time. (These choices are made randomly and independently of each other.) The probabilities were assigned using the relative frequency approach . Define event B as the event that roommate B wins the game and thus does not have to wash the dishes. What is P(B), the probability of event B? O P(B) = 0.67 P(B) = 0.30 P(B) = 0.38 O P(B) = 0.32 Let event C be the event that the game ends in a tie. What is P(C), the probability of event C? O P(C) = 0.44 P(C) = 0.25 O P(C) = 0.50 P(C) = 0.45Define event A as the event that roommate A wins the game and thus does not have to wash the dishes. What is the probability that roommate A wins the game? 7' P(A) = 0.67 7', P(A) = 0.24 7' P(A) = 0.37 o P(A) = 0.39 What is the complement of event B? o B = event A or event C 7' B = eventA 7' B = event C 7' B0 = event B or event C The probability of 3 is 0.61 v
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