Question: > higher _ order _ lambda = lambda f : lambda x : f ( x ) g = lambda x : x * *

> higher_order_lambda = lambda f : lambda x:f(x)
g= lambda x:x**x
higher_order_lambda(2)(g) # Which argument belongs to which function call?
higher_order_lambda(g)(2)
call_thrice = lambda f: lambda x:f(f(f(x)))
call_thrice(lambda y:y+1
print_lambda = lambda z: print(z) # When is the return expression of a lambda expression ex
print_lambda
one_thousand = print_lambda(1000)
> one_thousand # What did the call to print_lambda return?
 > higher_order_lambda = lambda f : lambda x:f(x) g= lambda x:x**x

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