Homework: Week 15 Chapter 7 Question 13, 7.2.38-T HW Score: 48.97%, 6.37 of 13 points Part 6 of 6 Score: 0 of 1 Save A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kiloWatt-hours (KWh). You want to test this claim. You find that a random sample of 64 residential customers has a mean monthly consumption of 900 KWh. Assume the population standard deviation is 126 KWh. At a = 0.05, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and Ha. Choose the correct answer below. O A. Ho: HS 900 *B. Ho: HS860 Ha: H > 900 (claim) Ha: H > 860 (claim) O C. Ho: H = 900 XD. Ho: H > 900 (claim) Ha: H #900 (claim) Ha: H $ 900 O E. Ho: H > 860 (claim) OF. Ho: H= 860 (claim) Ha: HS 860 Ha: H # 860 (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical values are + B. The critical value is 1.64. Identify the rejection region(s). Select the correct choice below. A. The rejection region is z > 1.64. * B. The rejection regions are z 1.64. O C. The rejection region is z 870 (claim) Ha: H # 870 O C. Ho: HS 900 O D. Ho: H > 900 (claim) Ha: H > 900 (claim) Ha: HS 900 O E. Ho: H = 900 OF. Ho: H > 870 (claim) Ha: H #900 (claim) Ha: HS 870 Click to select your answer and then click Check Answer. Help Me Solve This View an Example Get More Help - Clear All Check