How can I solve these problems USING R PROGRAM?(I NEED R CODES!) HELP ME PLZ!

1. In an experiment to investigate the suitability of using a silicone tube to model the behavior of a human artery, the data set in DS 12.8.4 is collected, which relates the pressure differential P across the walls of the tube to the cross-sectional area A of the tube.

(a) Show that the model P = (0)^(1) appears to provide a good fit to the data set.

(b) Make a suitable transformation of the variables and find point estimates for 0 and 1.

(c) Calculate two-sided 95% confidence intervals for 0 and 1.

2. A crack in a plastic compound affects the strength of the material. In order to investigate the relationship between the strength and the length of a crack, an experiment was conducted where cracked pieces of the plastic compound were subjected to increasing loads until the point at which they broke apart. DS 12.8.5 has the data set of the breakage loads and the lengths of the cracks. Show that a linear regression model with breakage load as the dependent variable and crack length as the explanatory variable is unsatisfactory because the residuals are first positive, then negative, and then positive again. Show that a better fit can be obtained with the model.

breakage load = 0^(1( ))

Using this model, what is the expected breaking load when the crack length is 2.1?

DS 12.8.4

'Pressure Differential' 'Cross-Sectional Area' 2 .5 4 .5400000214576721 7 .5699999928474426 11 .6499999761581421 13 .6899999976158142 21 .7300000190734863 32 .7799999713897705 48 .8500000238418579 64 .9700000286102295 91 1.0399999618530273

DS 12.8.5

'Crack Length' 'Breakage Load' .9900000095367432 7.46999979019165 1.1299999952316284 7 1.1399999856948853 6.820000171661377 1.3300000429153442 6.699999809265137 1.5199999809265137 5.679999828338623 1.5499999523162842 5.389999866485596 1.7799999713897705 4.809999942779541 1.9600000381469727 4.440000057220459 2.299999952316284 4.190000057220459 2.6500000953674316 3.319999933242798 3.059999942779541 2.390000104904175 3.109999895095825 2.5 3.1700000762939453 2.700000047683716 3.509999990463257 1.8200000524520874 3.7200000286102295 1.75