How can satellites stay in orbit without any jet propulsion system? Choose the correct explanation. O...

  

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How can satellites stay in orbit without any jet propulsion system? Choose the correct explanation. O Since the gravitational force is perpendicular to the direction of velocity at every instant, it does negative work on the satellite, thus the kinetic energy of the satellite remains constant, as thus the speed does not change. O Since the gravitational force is perpendicular to the direction of velocity at every instant, it does positive work on the satellite, thus the kinetic energy of the satellite remains constant, as thus the speed does not change. Since the gravitational force is perpendicular to the direction of velocity at every instant, it does not work on the satellite, thus the kinetic energy of the satellite remains constant, as thus the speed does not change. Submit Request Answer In the equation Ug = mgy, the gravitational potential energy is directly proportional to the distance of the object from a planet. In the equation Ug = - G O U₂=-G- == O Uga mpm = G 72 O Ug = = == -G- mpm T == mpm T -G- O The equation U₂ = = -G = mpm (RE+h)² mpm RE+h mpm RE+h -G Submit Request Answer 2 -G G mpm R² mpm RE mpm RE (1-2h) 1+ 1) = U₂0 + mgh where Uo h RE h (1-A/R) = U₂0 +mgh' where Ugo is our reference point. is our reference point. =)= U₂0 + mgh where U₁0 is our reference point. 90 G- mpm is suitable only for planets and stars, the equation Ug = mgy is suitable only on Earth. T mpm -, it is inversely proportional. How can you reconcile those two equations? T How can satellites stay in orbit without any jet propulsion system? Choose the correct explanation. O Since the gravitational force is perpendicular to the direction of velocity at every instant, it does negative work on the satellite, thus the kinetic energy of the satellite remains constant, as thus the speed does not change. O Since the gravitational force is perpendicular to the direction of velocity at every instant, it does positive work on the satellite, thus the kinetic energy of the satellite remains constant, as thus the speed does not change. Since the gravitational force is perpendicular to the direction of velocity at every instant, it does not work on the satellite, thus the kinetic energy of the satellite remains constant, as thus the speed does not change. Submit Request Answer In the equation Ug = mgy, the gravitational potential energy is directly proportional to the distance of the object from a planet. In the equation Ug = - G O U₂=-G- == O Uga mpm = G 72 O Ug = = == -G- mpm T == mpm T -G- O The equation U₂ = = -G = mpm (RE+h)² mpm RE+h mpm RE+h -G Submit Request Answer 2 -G G mpm R² mpm RE mpm RE (1-2h) 1+ 1) = U₂0 + mgh where Uo h RE h (1-A/R) = U₂0 +mgh' where Ugo is our reference point. is our reference point. =)= U₂0 + mgh where U₁0 is our reference point. 90 G- mpm is suitable only for planets and stars, the equation Ug = mgy is suitable only on Earth. T mpm -, it is inversely proportional. How can you reconcile those two equations? T

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Part A Satellites Can stay in orbit without propulsion system because any the g... View the full answer