Question: How can such integration be solved by hand? This is common in thermodynamics textbooks. Please show work how this integration is done IDCPH(298.15,418.15;1.376,4.157E3,1.610E6,0.121E+5)=23.121IDCPS(298.15,418.15;1.376,4.157E3,1.610E6,0.121E+5)=0.0692

 How can such integration be solved by hand? This is common

How can such integration be solved by hand? This is common in thermodynamics textbooks. Please show work how this integration is done

IDCPH(298.15,418.15;1.376,4.157E3,1.610E6,0.121E+5)=23.121IDCPS(298.15,418.15;1.376,4.157E3,1.610E6,0.121E+5)=0.0692

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