Question: How did they get 0.01 for part C ? All the answers are correct but I am unsure how they got the area =0.01 Please

How did they get 0.01 for part C ? All the answers are correct but I am unsure how they got the area =0.01 Please help

A company surveyed 2200 men where 1122 of the men identified themselves as the primary grocery shopper in their household. a) Estimate the percentage of all males who identify themselves as the primary grocery shopper. Use a 98% confidence interval, Check the conditions first. b) A grocery store owner believed that only 43% of men are the primary grocery shopper for their family, and targets his advertising accordingly. He wishes to conduct a hypothesis test to see if the fraction is in fact higher than 43%. What does your confidence interval indicate? Explain. c) What is the level of significance of this test? Explain. a) Check the conditions for constructing a confidence interval. Select all necessary conditions that have the appropriate explanation below. LY A. 10% Condition: This condition is satisfied because 2200 men are less than 10% of the population of men. LY B. Randomization Condition: This condition is satisfied because there is nothing to indicate that the samples were not drawn randomly LY C. Success/Failure Condition: This condition is satisfied because there were more than 10 successes and failures. D. 10% Condition: This condition is not satisfied because 2200 men are more than 10% of the population of men. E. Nearly Normal Condition: This condition is satisfied because there is nothing to indicate that the underlying population is not Normal. F. Nearly Normal Condition: This condition is not satisfied because it is highly unlikely that the population of men is Normal. G. Success/Failure Condition: This condition is not satisfied because there were fewer than either 10 successes or failures.H. Randomization Condition: This condition is not satisfied because the samples were drawn from a convenience sample. Construct a 98% confidence interval for the sample proportion. The 98% confidence interval is ( 0.485 , 0.535 ). (Round to three decimal places as needed. b) What does the confidence interval say about the grocery store owner's hypothesis? Because 43 % is not in the interval we have strong evidence that more than 43 % of men identify themselves as the primary grocery shopper. (Type integers or decimals. Do not round.) c) Determine the level of significance of the hypothesis test in the previous part and justify it. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or a decimal. Do not round.) A. The level of significance is a = 0.01 . Since the grocery store owner's test is one-tailed, we have to halve the area in the tails of the confidence interval. O B. The level of significance is a = . Since the grocery store owner's test is one-tailed, the level of significance is equal to the area not covered by the confidence interval. O C. The level of significance is a = . Since the grocery store owner's test is two-tailed, the level of significance is equal to the area not covered by the confidence interval. O D. The level of significance is a = . Since the grocery store owner's test is two-tailed, we have to halve the area in the tails of the confidence interval
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