Question: How do i solve this? So suppose a car accelerates at a rate of 9.5 feet per second each second over the course of 22

How do i solve this?

So suppose a car accelerates at a rate of 9.5 feet per second each second over the course of 22 seconds. Then f (t) = 4.75t2 where d = f(t). The practical range using interval notation would be

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