Question: how do we get the solution of 0.0595 for part ii 0120 Maximin littleg hood 1000082500047500047500015,81225004275 004275 0.025 Take 100 oll cll 011100100100 oll Higher

how do we get the solution of 0.0595 for part ii
how do we get the solution of 0.0595 for part ii 0120
Maximin littleg hood 1000082500047500047500015,81225004275 004275 0.025 Take 100 oll cll 011100100100 oll

0120 Maximin littleg hood 1000082500047500047500015,81225004275 004275 0.025 Take 100 oll cll 011100100100 oll Higher Value mistere give oll Rat for decision Minene give oill M(011)0595 (b) Alice and Bob switch to using binary communication. They design a code with codewords C={011,100} and pass it through an extended binary asymmetric channel, where the probability of 0 flipping to 1 is 0.05 and 1 flipping to 0 is 0.1. (i) The input probability of the codewords p is unknown. Which decision 2+1+ph rule should Alice and Bob use at the receiver? (ii) Calculate the mistake probability when 011 is sent, according to the 100 rule you suggested in (i)

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