How do you code missing.c ?

Int array[26] ={0}

Char str[100];

Int I=0;

Int missing;

Int total=0;

Hints: Recall that the statement rand ( ) % 100 will generate a random number in the range of 0 to 99. Use an array of 100 elements to store the number of times you've seen the values 0,1,2,... 99 Initialize this array to zeroes, and also use srand (0) to seed your random number generator. Your program should read in a number, and then generate that many random numbers. For each random number generated, increment that location in the array by one. . .After generating that many random numbers, count how many elements in the array are non-zero. Name this program missing.c-This program's input is a series of words. All words consist of only lower- case letters (a - z), no upper-case letters or digits or punctuation or other special symbols. The program reads until end-of-file, and then prints out the lower-case letters that were not seen in the input. Two executions of the program are shown below Enter your input : the quick brown Eox jumps over the lazy old dog Missing letters: Enter your input roll tide Missing letters: a bcf ghjk m n p qs u v w x y z Hints: Use an array of 26 elements to store the number of times you have seen the characters 'a' through 'z Initialize that array to zeroes, and then increment a given location when you see that letter Recall that lowercase letters are ASCII 97 (a) through ASCII 122 (z). If you subtract 97 from a givern character, you get a value in the range of 0 to 25 S.c hether or not any of the digits in that number occur more than once. Two sample executions are: nter a number: 12345 o duplicate digits found nts: Enter a number: 314159 Duplicate digits found Set up a loop that runs as long as your number is greater than zero