How do you determine if a list is odd in scheme? Example :

> ( isodd ( 1 2 3 6 ))

False

> ( isodd (1 3 5 7))

True

Note: you are not counting the number of items in the list. You are evaluating each number in the list. The numbers in the list are either all odd, which causes the function to output true else the function should output false. Also note that if the list is empty then it should also output true.