How long will it take you to convert $98\%$ of the silver perchlorate? If you use a vessel containing $30d{m}^3$ of solution, starting with $0\mathrm{.}7MC{H}_3$I and $0\mathrm{.}5MAgCl{O}_4$ concentrations.

The reaction stoichiometry is $C{H}_{3}I+AgCl{O}_{4}C{H}_{3}Cl{O}_4+$AgI

While the rate equation takes the form: $r_{C{H}_{3}l}=-k{C}_{C{H}_{3}1}{C}_{AgCl{O}_4}^{\frac{3}{2}}$

Batch Process

$,V=30d{m}^3$

$,C_{Bo}=0\mathrm{.}7mo\frac{l}{d}{m}^3$

$,C_{A0}=0\mathrm{.}5mo\frac{l}{d}{m}^3$

$,r_B=-k{C}_A{C}_B^{\frac{3}{2}}$atT$=298K$

$,k=0\mathrm{.}00042\frac{(d\frac{m^3}{m}ol{)}^{\frac{3}{2}}}{s}$

Final $x=0\mathrm{.}98$