Question: How many solutions does the equation sin 2x = 0.55 -x have? Use Newton's method to find them. Compute successive approximations to find the solution(s)

How many solutions does the equation sin 2x = 0.55 -x" have? Use Newton's method to find them. Compute successive approximations to find the solution(s) to five decimal places. The equation has 2 solution(s). (Type a whole number.) The solution(s) is/are x = (Use a comma to separate answers as needed. Type an integer or decimal rounded to five decimal places as needed.)

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