How many solutions in positive integers (0 isn't positive, of course) of a+b+c+d+e+ f = 18...

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How many solutions in positive integers (0 isn't positive, of course) of a+b+c+d+e+ f = 18 exist? We count 3+3+3+3+5+1 and 3+3+3+5+1+3 as distinct solutions. In how many of them all the numbers a, ..., f are odd, and in how many exactly four of them are even? How many solutions in positive integers (0 isn't positive, of course) of a+b+c+d+e+ f = 18 exist? We count 3+3+3+3+5+1 and 3+3+3+5+1+3 as distinct solutions. In how many of them all the numbers a, ..., f are odd, and in how many exactly four of them are even?

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To find the number of solutions in positive integers for the equation abc de f 18 where each variabl... View the full answer