Question: How much cobalt - 6 0 ( t 1 / 2 = 5 . 2 4 years ) ( t 1 / 2 = 5

How much cobalt-60(t1/2=5.24years)(t1/2=5.24years) must be used to make a laboratory source whose activity will exceed 3.0 GBqGBq for a period of 1.5 years?

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