how that the Boolean function $($x$1$ x$2)($x$1$x$2)$ is not linearly separable $($i$.$e$.$ there

is no linear classifier sign$($w$1$ x$1+$ w$2$ x$2+$ b$)$ that classifies all $4$ possible input points

correctly$).$ Assume that $$true$$ is represented by $1$ and $$false$$ is represented by $1.$ Show

that there is a linear separator for this Boolean function when we use the kernel K$($x$,$ y$)=$

$($x $$ y$)2$

$($x$.$y denotes the ordinary inner product$).$ Give the weights and the value of b for

one such separator.