how the logical address change to this form?

4. [20 points] Assume the following memory contents Address Contents F4 90 09A0.0000CS 09A0:0010 FE 09A0:0020 A7 09A0.0030 76 AS 02 9A 09 9B 67 89 D7 00 DS BD FF 12 A4 SE D8 BC 8A 90 71 34 70 2C 18 BB DD 00 24 72 3C 90 A8 A3 83 13 76 29 65 8C 93 01 19 39 D4 F6 58 OF CE SA C6 9E OE 40 2C 09A0:0040 82 A6 54 2E 9A 20 OA 98 E4 OE 25 38 29 20 86 And assume the following register contents DS: 09A2, SS: 09A0, ES: 09A1, BX=000F, BP:0012, SI: 0008, DI:0004, CX: 0002 Give the final value of the affected register: a) mov al, [SI] b) mov cx, [BX+3] c) mov dl, [BP+8] Answer: a) mov al, [SI] { DS:SI] =I 09A2:0008] = {09A0:0028). AL=IC b) mov cx, [BX+3] [DS:BX+3) = (09A2:000F+3] = { 09A2:0012] = [09A0:0032), AX= FFCA c) mov dl, [BP+8] [ SS:BP+8] =[09A0:0012+8}={09A0:001A), di = 9B