Question: How to round a single precision float point in mips? If I have to hex: 1st: 0x3B6BBBBB and 2nd: 0xC2F00000. After I MultFloats, I get

How to "round" a single precision float point in mips? If I have to hex: 1st: 0x3B6BBBBB and 2nd: 0xC2F00000. After I MultFloats, I get a number which is more than 32 bits, but I want to round and normalize it to a 32 bits number (0xBEDCFFFF). Could someone explain about this?

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