Question: How to solve 1 . 3 . In a test on a furnace fired with natural gas ( composition 9 5 % methane, 5 %

How to solve
1.3. In a test on a furnace fired with natural gas( composition 95% methane, 5% nitrogen), the following flue gas analysis was obtained:9.1% carbon monoxide 0.2%,oxygen 4.6%,nitrogen 86.1%, all percentages by volume. Calculate the percentage excess air flow (percentage above stoichiometric).
Solution
Reaction: CH4+2O2CO2+2H2O
Note: the flue gas analysis is reported on the dry basis, any water formed having been condensed out.
Nitrogen is the tie component.
Basis: 100 mol, dry flue gas; as the analysis of the flue gas is known, the mols of each element in the flue gas (flow out) can be easily calculated and related to the flow into the system.
Let the quantity of fuel (natural gas) per 100mol dry flue gas be x.
Balance on carbon, mols in fuel = mols in flue gas
0.95x=9.1+0.2, hence x=9.79mol??
Balance on nitrogen (composition of air O221 per cent, N279 per cent).
Let Y be the flow of air per 100mol dry flue gas.
N2 in air +N2 in fuel =N2 in flue gas
0.79Y+0.059.79=86.1, hence Y=108.4(mol)??
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 How to solve 1.3. In a test on a furnace fired

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