Question: how to solve 2. The differential equation x (x - 2) y+3(x - 2)y' + y = 0, has the singular points at x =

how to solve

2. The differential equation x (x - 2) y"+3(x - 2)y' + y = 0, has the singular points at x = 0 and x = 2. Classify them as either regular or irregular singular point. (Hint: Use substitution t = x - a for the singular point x = a). (4 marks)

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