Question: In Fig Q3, a D.C. shunt motor takes an armature current laj of 30A from a 500V D.C. Q3 supply. It runs at N1

In Fig Q3, a D.C. shunt motor takes an armature current laj

In Fig Q3, a D.C. shunt motor takes an armature current laj of 30A from a 500V D.C. Q3 supply. It runs at N1 = 1500 rev/min. Its total armature resistance Raj is 0.22. The motor speed is decreased by the use of armature resistance control. (a) Calculate the induced emf El of the motor at N1 = 1500 rev/min. (5 marks) (b) Calculate the induced emf E2 of the motor if its speed is decreased to (5 marks) N2 = 1200 rev/min. (c) Assume Ta N where T is the motor torque, N is the motor speed. (5 marks) Calculate the new armature current la2 of the motor when speed is N2 = 1200 rev/min. (d) Based on part (c), calculate the value of additional resistance Radd (5 marks) required in series with the Ra, = 0.2 0 resistance in the motor armature circuit to decrease the motor speed to N2 = 1200 rev/min. Iaj=30A 0.22 (Constant flux 0) 500V Shunt E1 1500 rpm Field Fig Q3

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