Question: how to solve Exercise 2 (4 marks) Pea plants contain two genes for seed color. each of which may be '1' [for yellow seeds] or
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Exercise 2 (4 marks) Pea plants contain two genes for seed color. each of which may be '1' [for yellow seeds] or G {for green seeds). Plants that contain one of each type of gene are called heterozygous. According to the Mendelian theory of genetics, if two heterozygous plants are crossed. each of their offspring will have probability 0.?5 of having yellow seeds and probability 0.25 of having green seeds. a) Out of IO offspring of heterozygous plants. at} what is the probability that exactly 3 have green seeds? a2} what is the probability that more than 2 have green seeds? b] Out of 100 offspring of heterozygous plants, bl} what is the probability that more than 30 have green seeds? b2} what is the probability that between 30 and 35 inclusive have green seeds? [Hint apply the normal distribution to the binomial distribution and continuity correction by extending 0.5 away from the values] Exercise 3 (2 marks) Consider a fair coin. a] What is the probability of obtaining exactly 3 heads if a fair coin is flipped 6 times? b] What is the probability of obtaining of least 4 head if a fair coin is flipped 17 times
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