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U25 x v fx A C D G . B Arrivals 1 Day 2 3 4 5 1 2 3 4 5 6 ON 0 9 7 NO OO 8 7 0 0 0 0 6 2 0 ww E E 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 SANNA 8 9 10 11 12 13 14 15 16 17 18 19 20 23 22 23 24 25 26 27 28 29 30 31 32 33 34 NN E C D E F Station 1 Station 2 Station 3 Completed 2 0.23 0.24 0.06 1 0.18 0.28 0.14 2 0.17 0.34 0.27 1 0 0.01 1 2 0.23 0.3 0.11 1 1 0.12 0.23 0.01 2 0 2 0.15 0.04 0 0 2 0.31 0.56 0.62 3 3 0.35 0.63 0.24 4 1 0.12 0.11 0.05 0 3 0.31 0.2 0.43 1 0:29 0.62 0.38 3 2 0.23 0.47 0.78 4 0.21 0.32 0.21 1 6 0.7 0.65 0.73 2 0.18 0.51 0.36 5 1 0.17 0.35 0.13 2 2 0.23 0.22 0.13 1 2 0.23 0.38 0.18 2 3 0.35 0.53 0.34 4 0.47 0.53 0.27 3 4 0.47 0.77 0.46 4 5 0.41 0.52 0.82 3 4 0.64 0.94 0.8 5 2 0.23 0.55 1 1 0.12 0.3 0.08 3 4 0.4 0.4 0.34 2 0.27 0.37 0.14 2 4 0.62 0.81 1 3 0.35 0.65 0.6 5 0.12 0.39 0.26 3 0.4 0.31 0.55 1 2 0.42 0.81 0.76 S 0 0 0.11 0.09 1 7 0.54 0.48 0.29 2 3 0.52 0.99 0.74 6 5 0.48 0.66 0.42 4 5 0.49 0.96 0.59 5 0.9 0.94 0,39 5 0.85 0.32 6 0.31 0.24 0.23 1 0.5 0.77 1 4 0.23 0.5 0.14 0.35 0.55 0.35 3 0.35 0.51 2 0.69 4 11 081 1 0:28 6 0.99 1 0.26 0.62 1 0.91 5 E mmaN EE 34 SE SE 0.23 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 8 Bee & 36 37 38 39 40 41 42 43 44 45 46 47 45 DOWN E SED 0.79 0.79 9 49 54 2. Compute the average inventory. The potential answers are A: 1.23 units B: 138 units C: 15 units D: 1.75 units E: 2.18 units. E 3. Compute the average flow time. Suppose throughput is equal to orders completed re The potential answers are: A: 0.58 days B: 0.76 days C:061 days D: 0.67 days E o days U25 x v fx A C D G . B Arrivals 1 Day 2 3 4 5 1 2 3 4 5 6 ON 0 9 7 NO OO 8 7 0 0 0 0 6 2 0 ww E E 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 SANNA 8 9 10 11 12 13 14 15 16 17 18 19 20 23 22 23 24 25 26 27 28 29 30 31 32 33 34 NN E C D E F Station 1 Station 2 Station 3 Completed 2 0.23 0.24 0.06 1 0.18 0.28 0.14 2 0.17 0.34 0.27 1 0 0.01 1 2 0.23 0.3 0.11 1 1 0.12 0.23 0.01 2 0 2 0.15 0.04 0 0 2 0.31 0.56 0.62 3 3 0.35 0.63 0.24 4 1 0.12 0.11 0.05 0 3 0.31 0.2 0.43 1 0:29 0.62 0.38 3 2 0.23 0.47 0.78 4 0.21 0.32 0.21 1 6 0.7 0.65 0.73 2 0.18 0.51 0.36 5 1 0.17 0.35 0.13 2 2 0.23 0.22 0.13 1 2 0.23 0.38 0.18 2 3 0.35 0.53 0.34 4 0.47 0.53 0.27 3 4 0.47 0.77 0.46 4 5 0.41 0.52 0.82 3 4 0.64 0.94 0.8 5 2 0.23 0.55 1 1 0.12 0.3 0.08 3 4 0.4 0.4 0.34 2 0.27 0.37 0.14 2 4 0.62 0.81 1 3 0.35 0.65 0.6 5 0.12 0.39 0.26 3 0.4 0.31 0.55 1 2 0.42 0.81 0.76 S 0 0 0.11 0.09 1 7 0.54 0.48 0.29 2 3 0.52 0.99 0.74 6 5 0.48 0.66 0.42 4 5 0.49 0.96 0.59 5 0.9 0.94 0,39 5 0.85 0.32 6 0.31 0.24 0.23 1 0.5 0.77 1 4 0.23 0.5 0.14 0.35 0.55 0.35 3 0.35 0.51 2 0.69 4 11 081 1 0:28 6 0.99 1 0.26 0.62 1 0.91 5 E mmaN EE 34 SE SE 0.23 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 8 Bee & 36 37 38 39 40 41 42 43 44 45 46 47 45 DOWN E SED 0.79 0.79 9 49 54 2. Compute the average inventory. The potential answers are A: 1.23 units B: 138 units C: 15 units D: 1.75 units E: 2.18 units. E 3. Compute the average flow time. Suppose throughput is equal to orders completed re The potential answers are: A: 0.58 days B: 0.76 days C:061 days D: 0.67 days E o days