How to solve these 2 questions?

The answer I wrote in part 1 and part 2 of Q1 / part 1 of Q2 are correct.

-Q1

Question: On a windy day a wind blows from S 16.3 W with a speed of 14.23 In/s. In this question'i' represents a unit vector in the easterly direction andj represents a unit vector in the northerly direction. Part 1) Present the velocity of the wind relative to the ground in unit vector notation. mm = 3.99 i+ 13.7 j m/s Your last answer was interpreted as follows: 3.99 Your last answer was interpreted as follows: 13.7 Part 2) You are on a boat travelling S 14.3 E relative to the bank (ground) at a speed 294 m/s. What is the velocity of the wind relative to the boat? Give your answer in unit vector notation. vwrelb 2 1+ Jm/s Part 3) What is the velocity of the boat relative to the wind? Ln) U! vb rel w = 1+ Question: The graph shows how the acceleration of a cart along the x axis changes with time (Figure 1). The cart starts with a speed 00 = 4.00 m/S, at x = 5.63 In. Inthe graph, 0A 2 3.09 Ins2, IA 2 9.41 S and t3 = 18.82 S. Give your answers with the correct number of signicant gures. a (In 52) \"A 0 t t A B t (S) Figure 1: A horizontal and a vertical line connecting the acceleration and time axes to the coordinate (IA, cm) on an acceleration-time graph. Another point is marked on the graph at the coordinate (t3, 0). Part 1) What is the velocity of the cart along the x axis at 4.70 S? Ux = 10.5 im/s Your last answer was interpreted as follows: 10.5 Part 2) Write an expression for the velocity of the cart along the x axis between t = 0 andt 2 IA 2 9.41 S. 0x = 3.09*t4.00 i m/s Your last answer was interpreted as follows: 3.09 - l' 4.00 The variables found in your answer were: [1'] Part 3) What is the position of the cart atl' = t3 = 18.82 S ? Feedback for Part 3) A velocity vs time graph would look like Figure 2, where DA 2 ()0 + aAtA m/S. Figure 2: A velocity-time graph of the described scenario. A diagonal line connects the coordinate (0, Do) on the negative velocity axis with the coordinate (IA, DA). A horizontal line connects this coordinate with the coordinate (1'3, (1,4). The area over the curve between the coordinate (0, U0) and the time axis is dened as Area 1. The area under the curve between the time axis and the coordinate (IA, 0A) is dened as Area 2 and the area under the curve between this coordinate and the coordinate (r3, DA) is dened as Area 3. The displacement is then the area under this curve. The area before the velocity graph crosses the x axis is negative and needs to be subtracted. One way to solve this is to split the area into two triangles and a rectangle labelled l, 2 and 3 on the graph. Do: area 2 + area 3 areal. Feedback for Part 2) You have incorrectly entered the rst component. You have incorrectly entered the second component. Write down the velocity of the boat (Figure 2) in unit vector notation: 9,5 = 1);, sin(65)i vb cos(6'b)j. A then use ewrelb 2 9w vb. N b vb Figure 2: A diagrammatic representation of the described motion of the boat on a north/southeast/west plane. A south-easterlydirected diagonal vector, 05,, connects the origin with a coordinate in the south eastern quadrant to the southern axis, and an easterly-directed horizontal vector connects the southern axis to this coordinate. The angle between 0;, and the southern axis is dened as 9b. Feedback for Part 3) You have incorrectly entered the rst component. You have incorrectly entered the second component. This is given by: A A brelw = 6b _ 6w = _(Vw _ Vb) where {'w {73, is your answer to the second part