How to solve these 3 different questions?

( 2 marks ) Consider the function f : R > IR defined by an) = 4a: +8taII1 at. First let us evaluate f(1) (in the exact form). f(1)= -42*Pi o n E . Let us notice that f is function. Also we can get f' (m) = 4+8/(1+x/\\2) o n . Q . Now we can conclude that f has an inverse function as it is on the whole domain (which doesn't have any gaps). Let us denote the inverse function of f by y where g : R ) R. News _III@- Then, (2 marks) Consider the function f : 1R \\ {2, 3} > R defined by Now we can conclude that the graph of f has horizontal asymptote(s) and vertical asymptote(s). In addition, 1' has an oblique asymptote y = Am + B where (2 marks) Consider the iunction f : [2, 1] > R defined by f(m)=m2+5. On the interval [2, 1] the maximum value off is and the minimum value is . Similarly, on the interval [0, 1] the maximum value off is and the minimum value is . Hence the values of upper and lower Riemann sum, E1; and p respectively, for function f with respect to the partition 'P = {2,1,0,1} are