Question: how to solve this 3= 1 0:40 (A) 0.5199 (B) 0.6064 (C) 0.602 10000 95-04 25. with mean 253 grains and standard deviation 3 grams.

how to solve this

3= 1 0:40 (A) 0.5199 (B) 0.6064 (C) 0.602 10000 95-04 25. with mean 253 grains and standard deviation 3 grams. A sample of five of these chocolate bars is selected. There is only a 2.5% chance that the average weight of the sample will be below: 120 (A) 250.37 grams (B) 254.10 grams 1,3717 (C) 252.63 grams. (D) 251.54 grams 55 (E) 249.82 grams M-253 3 320 2017 0.0102375 in 0.025 1012 011

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