How to solve this one?

Consider the curve with parametric equation a(t) = [222+ 1,t2 +3t+2] ,t e R. The equation of the: . tangent to the curve at the point (1(1) is y = a . normal to the curve at the point a(1) is y = E a. By eliminating the parameter t , we nd that the Cartesian equation of the curve is: y= -m The curve (in black). tangent (in blue) and normal (in red) are displayed below