Question: How to solve this system of equations using Rouche Theorem? (2x+5y-2z-3t = 0 x+2y-3z+t=1 x+4y-5z+2t = 3

How to solve this system of equations using Rouche Theorem?

( left{begin{array}{l}2 x+5 y-2 z-3 t=0 x+2 y-3 z+t=1 x+4 y-5 z+2 t=3end{array}ight. ) 

(2x+5y-2z-3t = 0 x+2y-3z+t=1 x+4y-5z+2t = 3

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