How to solve ?

Unit 5: Polynomial Functic 7. The path of a baseball after it is hit is modelled by the equation h =-4.9812 +12.51t +1.36, where h is the height, in metres, of the ball and t is the time, in seconds, after the ball is hit. a. Find the maximum height that the ball reaches, to the nearest hundredth of a metre. (1 mark) 9 = - 4.98+2 + 12.51+ + 1. 36 max = 9.22 metre b. Determine the height of the ball, to the nearest hundredth of a metre, at 2.5 seconds. (1 mark) X = 2. 5 y = - 4. 98 (2.5) + 12.5 1 ( 2. 5 ) + 1. 36 y = 1.51 m = - 31. 125 + 31.275 +1.36 c. Determine when the ball is at a height of 8m, to the nearest hundredth of a second. (2 marks y = 8m x = 1, 75 sec X = 0. 76 sec d. State the y-intercept of the graph to the nearest hundredth. Describe what the y-intercept represents in the context of this question. (2 marks) e. i. Find the coordinates of both x-intercepts of the graph to the nearest hundredth. (2 m ii. State what the positive x-intercept represents in the context of this problem. (1 ma iii. Explain why the negative x-intercept is not valid in the context of this